Students were asked over to answer a question at academics and to say what is most important for them to succeed. Of many results, one that that stood out was practice. Successful persons ordinarily are not born successful; they become successful with hard work and dedication. This is how you can achieve your goals. in the following paragraphs are one of the answer and question example that you might possibly use to practice and supercharge your information and also give you insights that may guide you to maintain your study in school.
Question:
. A lightbulb with a resistance of 2.9 ohms is operated using a 1.5-volt battery. At what rate iselectrical energy transformed in the lightbulb?
Answer:
Answer:
Explanation:
Given that,
A light bulb has a resistance of 2.9ohms
R = 2.9 ohms
And a battery of 1.5V is applied
V = 1.5 V
We want to find the rate of energy transformed
First we need to know what rate of energy is
Rate of energy implies that we want to find power. Power is the rate at which work is done
P = Workdone / time
Then,
In electronic, the power dissipated by a resistor is given as
P = V² / R
P = 1.5² / 2.9
P = 0.7759 W
P ≈ 0.776 W
So, the rate at which electrical energy transformed in the lightbulb is 0.776 Watts
They could hopefully help the student sort out the question by obtaining the questions and answer examples. Then would possibly have some sharing in a group discussion and also learning with the classmate with regards to the topic, so another student also ought to have some enlightenment and still keeps up the school learning.