# A lightbulb with a resistance of 2.9 ohms is operated using a 1.5-volt battery. At what rate iselectrical energy transformed in the lightbulb?

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## Question:

. A lightbulb with a resistance of 2.9 ohms is operated using a 1.5-volt battery. At what rate iselectrical energy transformed in the lightbulb?

Explanation:

Given that,

A light bulb has a resistance of 2.9ohms

R = 2.9 ohms

And a battery of 1.5V is applied

V = 1.5 V

We want to find the rate of energy transformed

First we need to know what rate of energy is

Rate of energy implies that we want to find power. Power is the rate at which work is done

P = Workdone / time

Then,

In electronic, the power dissipated by a resistor is given as

P = V² / R

P = 1.5² / 2.9

P = 0.7759 W

P ≈ 0.776 W

So, the rate at which electrical energy transformed in the lightbulb is 0.776 Watts

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