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## Question:

Which of the following is an extraneous solution of mc015-1.jpg? x = –12 x = –3 x = 3 x = 12

## Answer:

the answer

the full the question is as follow:

Which of the following is an extraneous solution of (45 – 3x)^1/2 =x -9

for solving such an equation, this is the method:

finding the squared value of each member of the equation

[(45 – 3x)^1/2 ]² = (x -9)² (E)

extend each value of the member

[(45 – 3x)^1/2 ]² = 45 – 3x, because (sqrt a )² = a

the condition is 45 – 3x≥0 ( because of the square root)

it means – 3x≥ -45 and x ≤ 15

(x -9)² = x²-18x + 81

so 45 – 3x = x²-18x + 81, this is equivalent to x² – 15x +36 =0

this equation should solve for x, for finding the help

Delta = 15² – 4*36 = 81, so x = – (-15) – sqrt (81) / 2 *1=15-9 /2= 3

and x = – (-15) +sqrt (81) / 2 *1= 15 +9/2= 24/2=12

for x= 12, the equation given above ( equation E) has no solution, because

we can find 3=9

so an extraneous solution is x = 12

They could certainly hopefully assist the student resolve the question by obtaining the questions and answer examples. You could potentially then have a discussion with your classmate and continue the school learning by studying the problem altogether.