A crate is pushed horizontally by a horizontal force 527.018 N . Sliding friction resists the motion, and the kinetic coefficient of friction is 0.17 . The acceleration of gravity is 9.8 m/s 2 . Calculate the acceleration of the crate. Answer in units of m/s 2 .

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Question:

A crate is pushed horizontally by a horizontal force 527.018 N . Sliding friction resists the motion, and the kinetic coefficient of friction is 0.17 . The acceleration of gravity is 9.8 m/s 2 . Calculate the acceleration of the crate. Answer in units of m/s 2 .

Answer:

Answer:

m= 10 kg a = 52 m / s²

Explanation:

For this problem we must use Newton’s second law, let’s apply it to each axis

X axis

      F – fr = ma

The equation for the force of friction is

    -fr = miu N

Axis y

     N- W = 0

     N = mg

Let’s replace and calculate laceration

     F – miu (mg) = ma

    a = F / m – mi g

    a = 527.018 / m – 0.17 9.8

We must know the mass of the body suppose m = 10 kg

    a = 527.018 / 10 – 1,666

    a = 52 m / s²

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