When 150 joules of work is done on a system by an external force of 15 newtons in 20. seconds, the total energy of that system increases by.

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Question:

When 150 joules of work is done on a system by an external force of 15 newtons in 20. seconds, the total energy of that system increases by.

(1) 1.5 × 102 J
(2) 2.0 × 102 J
(3) 3.0 × 102 J
(4) 2.3 × 103 J
Please include an explanation

Answer:

The total energy of that system increases by 150 Joule. The correct answer is option (1)

Given that 150 joules of work is done on a system by an external force of 15 newtons in 20 seconds

The impulse on the system = the momentum of the system

That is,

Ft = mV

15 x 20 = mV

mV = 300 Ns

Since work done = energy

W = 1/2mV x V

150 = 0.5 x 300V

V = 1 m/s

With this, we can calculate the acceleration and the distance travelled.

Using equation one of motion,

V = u + at

1 = 0 + 20a

a = 1/20

a = 0.05 m/

Using equation three of linear motion.

= + 2aS

Substituting all parameters into the equation

= 0 + 2 x 0.05 S

S = 1/0.1

S = 10 m

The work done = Force x distance

The work done = 15 x 10

The work done = 150 Joule.

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Therefore,  the total energy of that system increases by 150 Joule.

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