A 3 kg block rests on a rough horizontal table. A rope is attacked to the block and is pulled with a force of 11N to the left. As a result, the block accelerates at 3 m/s^2. The coefficient of kinetic friction between the block and the table is _ (round to the nearest hundredth)

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Question:

A 3 kg block rests on a rough horizontal table. A rope is attacked to the block and is pulled with a force of 11N to the left. As a result, the block accelerates at 3 m/s^2. The coefficient of kinetic friction between the block and the table is _ (round to the nearest hundredth)

Answer:

The coefficient of kinetic friction between the block and the table to the nearest hundredth is 0.07

According to Newton’s second law of motion:

is the sum of forces

m is the mass

is the acceleration

Fm is the moving force

Ff is the frictional force

The formula becomes

Given the following

m = 3kg

= 3m/s²

Fm = 11N

g = 9.8m/s²

Substitute the given values into the formula:

Hence the coefficient of kinetic friction between the block and the table to the nearest hundredth is 0.07

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