Complete the following radioactive decay problem. 238\92u arrow 4/2he 234/90th arrow 234/91pa ( ? ) 4/2he 1/1p 1/0n 0/1e 0/-1e

One recent schools question and answer asked students to declare what they believe is the most crucial important element for a student to do if they wanted to gain success. Of the many reactions, the one that that stood out was practice. Successful persons ordinarily are not born successful; they become successful by just hard work and persistence. If you would like to accomplish your goals, keep this in mind! followed below some question and answer examples that you can utilise to boost your knowledge and gain insight that will assist you to maintain your school studies.

Question:

Complete the following radioactive decay problem. 238\92u arrow 4/2he 234/90th arrow 234/91pa ( ? ) 4/2he 1/1p 1/0n 0/1e 0/-1e

Answer:

Here we have to complete the given radioactive decay reaction:

²³⁸₉₂U → ⁴₂He + ²³⁴₉₀Th → ²³⁴₉₁Pa ? ⁴₂He + ₁¹P + ¹₀n + ⁰₁e + ₋₁⁰e.

The completed radioactive reaction is

²³⁸₉₂U → ⁴₂He + ²³⁴₉₀Th → ²³⁴₉₁Pa + ⁴₂He + ₋₁⁰e (electron).

In any radioactive reaction the mass number and the atomic number of the reactant and product will be same respectively.

The mass number and atomic number of the reactant uranium (U) is 238 and 92 respectively. Thus in the last reaction if ⁴₂He is eliminated then the mass number of the product 234 + 4 – 0 = 238.

The atomic number will be 91 + 2 – 1 = 92.

Thus the missing particle is electron (₋₁⁰e)

From the answer and question examples above, hopefully, they can definitely guide the student solve the question they had been looking for and remember of all the pieces stated in the answer above. You could certainly then have a discussion with your classmate and continue the school learning by studying the topic jointly.

READ MORE  Which is a carbohydrate monomer? glucose sucrose glucagon glycogen

Leave a Reply

Your email address will not be published.