# Jason and Jenny are out on a lunch date. Jason gives Jenny a bouquet that has 4 roses, 3 carnations, and 4 orchids. They decide that Jenny gets to choose their lunch order if the flower she randomly picks from the bouquet is a carnation or a rose. What is the probability that Jenny gets to choose lunch?

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## Question:

Jason and Jenny are out on a lunch date. Jason gives Jenny a bouquet that has 4 roses, 3 carnations, and 4 orchids. They decide that Jenny gets to choose their lunch order if the flower she randomly picks from the bouquet is a carnation or a rose. What is the probability that Jenny gets to choose lunch?

Answer: The probability that Jenny gets to choose lunch =

Step-by-step explanation:

Choosing any color flower from the bouquet makes events mutually exclusive.

Now, the total number of flowers in the bouquet= 4+3+4 = 11

Number of rose=4

Probability of choosing a rose P(R)=

Number of carnations=3

Probability of choosing a carnation P(C)=

The probability of choosing a rose or a carnation

P(R or C)=P(R)+P(C)=

Thus, the probability that Jenny gets to choose lunch =

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