A 2000 kg car experiences a constant braking. force of 10,000 N, and comes to be a stop in 6. sec.. What would be the distance traveled by the. car in coming to rest?

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Question:

A 2000 kg car experiences a constant braking. force of 10,000 N, and comes to be a stop in 6. sec.. What would be the distance traveled by the. car in coming to rest?

Answer:

Given:

F = Force = 10000N
m = mass = 2000kg
t = time = 6 seconds
a = acceleration = ?

Using the formula: F = ma

10000 = 2000(a)
a = 5 m/s^2

Using the formula: Vf = Vo + at
Where: Vf = final velocity = 0
Vo = initial velocity = ?

0 = Vo + 5(6)
Vo = 30 m/s

Using the formula: s = (1/2)(Vf + Vo)(t)
s = (1/2)(30 + 0)(6)
s = 90

Therefore, the car would have traveled a distance of 90m before coming to rest.

From the answer and question examples above, hopefully, they can possibly guide the student resolve the question they had been looking for and observe of every single thing declared in the answer above. You might possibly then have a discussion with your classmate and continue the school learning by studying the problem together with each other.

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