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## Question:

A hollow conducting sphere has an inner radius of r1 = 0.19 m and an outer radius of r2 = 0.34 m. The sphere has a net charge of Q = 1.8E-06 C. What is the field E1 in N/C 1 m from the sphere’s outer surface?

## Answer:

We have that the **electric field **in N/C 1m from th**e sphere’s outer surface** is mathematically given as

**E = 9022.0539 N/C**

**Electric field**

Question Parameters:

- r1 = 0.19
- r2 = 0.34
- Q = 1.8 × 10⁻⁶ C

Generally the equation for the **Electric field** is mathematically given as

E= k × q/r²

Where

k = 9× 10^9

E= 9× 10^9 × 1.8 × 10^{-6}/ (1+0.34)2

**E= 9022.0539 N/C**

Therefore

The** electric field **in N/C 1m from th**e sphere’s outer surface**

**E = 9022.0539 N/C.**

For more information on **Electric Field **visit

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