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## Question:

Solve x4 – 17×2 + 16 = 0.

Let u =

Select all of the zeroes of the function. i i

## Answer:

The **zeros** of the equation are 4 and -4

**Given** the **polynomial** expression x^4 – 17x^2 + 16 = 0.

Reduce the** function** to a** quadratic function **

Let P = x²

The equation becomes;

(x²)² – 17x² + 16 = 0

P² – 17P + 16 =0

**Factorize **the result

P² – 16P – P+ 16 =0

P(P-16)-1(P-16) = 0

(P-16) (P-16) = 0

P = 16 twice

Since** P = x²**

x² = 16

x = ±√16

x = ±4

Hence the **zeros** of the equation are 4 and -4

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