unit 10: circles Homework 4: Inscribed angles. please complete the following questions and explain how it is done. ​

Students were enquired to answer a question at academics and to indicate what is most important for them to succeed. One which response stood out from the rest was practice. Successful persons ordinarily are not born successful; they become successful via hard work and dedication. If you want to attain your goals, keep this in mind! in the following paragraphs some question and answer examples that you can easily utilise to upgrade your knowledge and gain insight that will assist you to preserve your school studies.

Question:

unit 10: circles Homework 4: Inscribed angles. please complete the following questions and explain how it is done. ​

Answer:

5) The sum of angle in the triangle DEF is 180 degrees

mFE = <D

Recall that <D+<E+<F = 180⁰

<D+63+90 = 180

<D = 180-153

<D = 27 degrees

Hence the measure of arc FE is 27degrees

6) For this circle geometry, we will use the theorem

The sum of Opposite side of a cyclic quadrilateral is 180 degrees.

A + C = 180

m<A + 101 = 180

m<A = 180-101

m<A = 79degrees

Similarly

B + D = 180

m<B + 68 = 180

m<B = 180-68

m<B = 112degrees

7) The sum of angle in a circle is 360, hence;

arcGJ+68+31+115 = 36p

arcGJ = 360 – 214

arcGJ = 146⁰

Since the angle at the centre is twice angle at the circumference, then;

<GHJ = 1/2 arcGJ

<GHJ = 1/2(146)

<GHJ = 73⁰

<GHJ = <GIJ = 73⁰ (angle in the same segment of the circle are equal)

8) Recall that the sum of Opposite side of a cyclic quadrilateral is 180 degrees.

P + R = 180

57 + <R = 180

m<R = 180-57

m<R = 123degrees

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Similarly, m<Q+m<S = 180⁰

Since the triangle in a semi circle is a right angled triangle, hence m<Q = 90 degrees (triangle PQR is a right angled triangle)

m<S = 180 – 90

m<S = 90 degrees

Learn more here: brainly.com/questions/1132554

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