The vertices of ∆ABC are A(2, 8), B(16, 2), and C(6, 2). what is the perimeter and area in square units

Students were enquired to answer a question at schools and to mention what is most important for them to succeed. The one which response stood out from the rest was practice. Successful persons are not born successful; they become successful via hard work and determination. This is how you can complete your goals. as follows some question and answer examples that you could potentially utilise to enriches your knowledge and gain insight that will help you to preserve your school studies.

Question:

The vertices of ∆ABC are A(2, 8), B(16, 2), and C(6, 2). what is the perimeter and area in square units

Answer:

Best is to draw a sketch of the three points.
Next step is to find the distances BC, CD, DB.
The perimeter is the sum of the three distances.

The distances are found using the distance formula:
D=sqrt((y2-y1)^2+(x2-x1)^2)
order of (x1,y1), (x2,y2) is not important.

Given A(2,8),B(16,2),C(6,2)
we calculate 
AB=sqrt((16-2)^2+(2-8)^2)=sqrt(14^2+6^2)=sqrt(232);
BC=sqrt((6-16)^2+(2-2)^2)=sqrt(10^2+0)=10
CA=sqrt((2-6)^2+(8-2)^2)=sqrt(4^2+6^2)=sqrt(16+36)=sqrt(52)

Perimeter=AB+BC+CA=32.443 units

For the area, we note that BC is horizontal (parallel to the x-axis), so 
area = (1/2)bast * height
=(1/2)10*(ya-yb)
=(1/2)10*(8-2)
=(1/2)10*6
=30 unit^2

From the answer and question examples above, hopefully, they may assist the student handle the question they had been looking for and take note of all the stuff declared in the answer above. You can then have a discussion with your classmate and continue the school learning by studying the subject alongside one another.

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