Students were inquired to answer a question at school and to say what is most important for them to succeed. The one that response stood out from the rest was practice. Successful people ordinarily are not born successful; they become successful by just hard work and commitment. If you want to accomplish your goals, keep this in mind! in this article, some question and answer examples that you could possibly make use of to develop your knowledge and gain insight that will assist you to continue your school studies.
Question:
Is AsBr3 polar or non-polar?
Answer:
Answer : is a polar molecule.
Explanation :
First we have to determine the hybridization of .
Formula used :
where,
V = number of valence electrons present in central atom
N = number of monovalent atoms bonded to central atom
C = charge of cation
A = charge of anion
Bond pair electrons = 3
Lone pair electrons = 4 – 3 = 1
The number of electron pair are 4 that means the hybridization will be and the electronic geometry of the molecule will be tetrahedral.
But as there are three atoms around the central arsenic atom, the fourth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be trigonal pyramidal.
Polar bond : It is defined as the covalent bonds in which the electrons are shared unequally (that result in partial charges) between the elements that have different electronegativity. In the polar bond, the electron cloud is in distorted form. Polar bonds have a dipole moment.
Non-polar bond : It is defined as the covalent bonds in which the electrons are shared equally (that result no charges) between the elements that have same electronegativity. In the non-polar bond, the electron cloud is not in distorted form. Non-polar bonds do not have a dipole moment.
In the given molecule, there is some dipole moment due to asymmetric molecule. So, the given molecule is polar.
Hence, is a polar molecule.
They would possibly hopefully guide the student deal with the question by making use of the questions and answer examples. You could potentially then have a discussion with your classmate and continue the school learning by studying the topic together.