A semi-circle sits on top of a rectangle to form the figure below. Find its area and perimeter. Use 3.14 for ππ .. 4 in L, Base 6in

Students were requested to answer a question at institution and to express what is most important for them to succeed. One which response stood out from the rest was practice. People who were successful do not become successful by being born. They work hard and commitment their lives to succeeding. This is how you can obtain your goals. in the following paragraphs are one of the answer and question example that you could definitely make use of to practice and boost your information and also give you insights that should help you to preserve your study in school.

Question:

A semi-circle sits on top of a rectangle to form the figure below. Find its area and perimeter. Use 3.14 for ππ .. 4 in L, Base 6in

Answer:

The area of the given figure is 38.13 in² and its perimeter is 23.42 in.

First, we will determine the area of the semicircle,

Area of a semicircle = Half area of a circle

Area of a circle =

∴ Area of semicircle =  

Where r is the radius

From the diagram, the base of the figure (length of the rectangle) equals the diameter of the semicircle

∴ diameter = 6 in.

But

r = 3 in.

Now, from

Area of semicircle =  

Area of the semicircle =  

Area of the semicircle =

Area of the semicircle = 14.13 in².

For the rectangle,

Area of rectangle =

Length = 6 in.

and the width = 4 in.

∴ Area of the rectangle = 6 × 4

Area of the rectangle = 24 in².

Now, for the area of the figure,

Area of the figure = Area of the semicircle + Area of the rectangle

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∴ Area of the figure = 14.13 in². + 24 in².

Area of the figure = 38.13 in².

For the perimeter of the figure,

Perimeter is sum of all sides

Perimeter of the figure = Width of rectangle + Length of rectangle + Width of rectangle + length of the half circumference

First, we will determine the length of the half circumference,

Length of the half circumference =

Length of the half circumference = 3.14 × 3

Length of the half circumference = 9.42 in.

From

Perimeter of the figure = Width of rectangle + Length of rectangle + Width of rectangle + length of the half circumference

∴ Perimeter of the figure = 4 in. + 6 in. + 4 in. + 9.42 in.

Perimeter of the figure = 23.42 in.

Hence, the area of the figure is 38.13 in² and its perimeter is 23.42 in.

From the answer and question examples above, hopefully, they could help the student resolve the question they had been looking for and notice of everything that declared in the answer above. You will possibly then have a discussion with your classmate and continue the school learning by studying the subject jointly.

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