How do I determine the number of atoms in 30.0 g of K

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How do I determine the number of atoms in 30.0 g of K


The number of atoms in 30.0 g of K would be 4.632  x atoms.

Avogadro’s number

1 mole of a substance contains 6.022 x atoms.

Mole of 30.0 g of K potassium = 30/39

                                                       = 0.7692 moles

Hence, 0.7692 moles of K would contain

                     0.7692 x 6.022 x   atoms.

                                = 4.632  x atoms.


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