How many moles are in 98.3 grams of aluminum hydroxide, Al(OH)3?

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Question:

How many moles are in 98.3 grams of aluminum hydroxide, Al(OH)3?

Answer:

Considering the definition of molar mass, 1.26 moles are in 98.3 grams of aluminum hydroxide, Al(OH)₃.

The given molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

The molar mass of a compound (also called Mass or Molecular Weight) is the sum of the molar mass of the elements that form it (whose value is found in the periodic table) multiplied by the number of times they appear in the compound.

In this case, you know the molar mass of the elements is:

  • Al= 27 g/mole
  • O= 16 g/mole
  • H= 1 g/mole

So, the molar mass of the compound Al(OH)₃ is calculated as:

Al(OH)₃= 27 g/mole + 3× (16 g/mole + 1 g/mole)

Solving:

Al(OH)₃= 78 g/mole

Next, you can apply the following rule of three: if 78 grams of the compound are contained in 1 mole, 98.3 grams are contained in how many moles?

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amount of moles= 1.26 moles

1.26 moles are in 98.3 grams of aluminum hydroxide, Al(OH)₃.

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