A rectangular schoolyard is to be fenced in using the wall of the school for one side and 150 meters of fencing for the other three sides. The area A(x) in square meters of the schoolyard is a function of the length x in meters of each of the sides perpendicular to the school wall.

Students were requested to answer a question at education and to tell what is most important for them to succeed. Of the numerous answers, the one which that stood out was practice. Successful persons generally are not born successful; they become successful via hard work and persistence. If you tend to get your goals, keep this in mind! in this article, some question and answer examples that you could simply benefit from to upgrade your knowledge and gain insight that will assist you to continue your school studies.

Question:

A rectangular schoolyard is to be fenced in using the wall of the school for one side and 150 meters of fencing for the other three sides. The area A(x) in square meters of the schoolyard is a function of the length x in meters of each of the sides perpendicular to the school wall. a. Write an expression for A(x).
b. What is the area of the schoolyard when x=40?
c. What is a reasonable domain for A in this context?

Answer:

The area of a shape is the amount of space on it.

  • The expression for A(x) is
  • The area when x = 40, is: 2800
  • The reasonable domain is:

The perimeter of the schoolyard is given as: 150

So, we have:

  • Where x and y represents the dimension of the schoolyard
  • The equation represents the sum of the three sides (because the 4th side is the wall of the school)

Substitute 150 for P

Make y the subject

The area (A) of a schoolyard is:

Substitute

Express as a function

The area when x = 40, is:

READ MORE  Discuss the two main causes of skin cancer.

x cannot be less than 0.

Also, we have:

Set to 0

Rewrite as:

Divide both sides by -2

So, the reasonable domain is:

Read more about area functions at:

From the answer and question examples above, hopefully, they might assist the student take care of the question they had been looking for and take note of all the pieces stated in the answer above. You could potentially then have a discussion with your classmate and continue the school learning by studying the problem together with each other.

Leave a Reply

Your email address will not be published.