# A motorcycle has a mass of 250kg. It goes around a 13.7 m radius turn at 96.5 km/hr. What is the centripetal force?

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## Question:

A motorcycle has a mass of 250kg. It goes around a 13.7 m radius turn at 96.5 km/hr. What is the centripetal force?a. 2.95×10^3 Nb. 4.31×10^4Nc. 1.31×10^4 Nd. 719N

The centripetal force of a motorcycle that has a mass of 250kg and goes around a 13.7 m radius turn at 96.5 km/hr is 1.31 × 10⁴N

HOW TO CALCULATE CENTRIPETAL FORCE:

• The centripetal force can be calculated by using the following formula:
• F = mv²/r

Where;

1. F = centripetal force (N)
2. m = mass of the object (kg)
3. v = velocity (m/s)
• According to this question, a motorcycle has a mass of 250kg. It goes around a 13.7 m radius turn at 96.5 km/hr.
• First, we need to convert 96.5km/hr to m/s as follows:
• = 96.5km ×1000/1hr × 3600
• = 96,500/3,600
• v = 26.8m/s
• F = (250 × 26.8²) ÷ 13.7
• F = 179560 ÷ 13.7
• F = 13,106.6N
• F = 1.31 × 10⁴N
• Therefore, the centripetal force of a motorcycle that has a mass of 250kg and goes around a 13.7 m radius turn at 96.5 km/hr is 1.31 × 10⁴N.

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