Some later institution question and answer asked over students to declare what they ponder is the most important important thing for a student to do if they wanted to gain success. Of many answers, one that that stood out was practice. People who commonly are successful do not become successful by being born. They work hard and dedicate their lives to succeeding. This is how you can get your goals. shown below some question and answer examples that you can easily utilize to further enhance your knowledge and gain insight that will guide you to continue your school studies.
How many grams of CaH2 are needed to generate 48.0 L of H2 gas at a pressure of 0.995 atm and a temperature of 32 °C?
We have to get the amount of CaH₂ needed to generate 48 L of H₂ gas at a pressure of 0.995 atm and a temperature of 32 °C.
The amount of CaH₂ required is 79.971 gram to generate 48 L of H₂ gas at a pressure of 0.995 atm and a temperature of 32 °C .
The number of moles of H₂ gas present in 48 litre H₂ gas at a pressure of 0.995 atm and a temperature of 32°C= = 1.90 moles [using PV=nRT equation where, n= ]
To obtain one mole H₂, one mole of CaH₂ is required. So, to get 1.90 moles of H₂ gas, 1.90 moles of CaH₂ is required.
Molecular mass of CaH₂ is 42.09 g/mol. So, amount of CaH₂ needed to generate 1.90 moles of H₂ gas is equal to (1.90 X 42.09) gm= 79.971 gm.
79.971 grams of CaH₂ are needed to generate 48.0 L of H₂ gas at a pressure of 0.995 atm and a temperature of 32 °C.
From the answer and question examples above, hopefully, they might help the student answer the question they had been looking for and notice of every single thing declared in the answer above. You will be able to then have a discussion with your classmate and continue the school learning by studying the topic alongside one another.