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A proton starts from rest and gains 8.35 x 10^-14 joule of kinetic energy as it accelerates between points A and B in an electric field. The potential difference between points A and B in the electric field is approximately
The potential difference between points A and B in the electric field is approximately equal to
Given the following data:
- Kinetic energy =
- Charge of proton =
To determine the potential difference between points A and B in the electric field:
Mathematically, kinetic energy is calculated by using this formula;
- K.E is the kinetic energy.
- q is the charge of a particle.
- is the potential difference of a particle.
Making the subject of formula, we have:
Substituting the given parameters into the formula, we have;
When is approximated, we have:
Potential difference = 522,000 Volts
Potential difference =
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