# A proton starts from rest and gains 8.35 x 10^-14 joule of kinetic energy as it accelerates between points A and B in an electric field. The potential difference between points A and B in the electric field is approximately

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## Question:

A proton starts from rest and gains 8.35 x 10^-14 joule of kinetic energy as it accelerates between points A and B in an electric field. The potential difference between points A and B in the electric field is approximately The potential difference between points A and B in the electric field is approximately equal to Given the following data:

• Kinetic energy = Scientific data:

• Charge of proton = To determine the potential difference between points A and B in the electric field:

Mathematically, kinetic energy is calculated by using this formula; Where:

• K.E is the kinetic energy.
• q is the charge of a particle.
• is the potential difference of a particle.

Making the subject of formula, we have: Substituting the given parameters into the formula, we have; When is approximated, we have:

Potential difference = 522,000 Volts

Potential difference = From the answer and question examples above, hopefully, they may help the student sort out the question they had been looking for and remember of all the things declared in the answer above. Then can certainly make some sharing in a group discussion and also study with the classmate about the topic, so another student also will have some enlightenment and still keeps up the school learning.

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