A proton starts from rest and gains 8.35 x 10^-14 joule of kinetic energy as it accelerates between points A and B in an electric field. The potential difference between points A and B in the electric field is approximately

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Question:

A proton starts from rest and gains 8.35 x 10^-14 joule of kinetic energy as it accelerates between points A and B in an electric field. The potential difference between points A and B in the electric field is approximately

Answer:

The potential difference between points A and B in the electric field is approximately equal to

Given the following data:

  • Kinetic energy =

Scientific data:

  • Charge of proton =

To determine the potential difference between points A and B in the electric field:

Mathematically, kinetic energy is calculated by using this formula;

Where:

  • K.E is the kinetic energy.
  • q is the charge of a particle.
  • is the potential difference of a particle.

Making the subject of formula, we have:

Substituting the given parameters into the formula, we have;

When is approximated, we have:

Potential difference = 522,000 Volts

Potential difference =

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