Students were asked over to answer a question at academics and to indicate what is most important for them to succeed. Out of the many answers, the one which that stood out was practice. People who commonly successful do not become successful by being born. They work hard and dedication their lives to succeeding. This is how you can attain your goals. Below some question and answer examples that you can utilise to enhance your knowledge and gain insight that will help you to preserve your school studies.

## Question:

Which of the following represents a valid probability distribution?Probability

Distribution A

X

P(x)

olo

Probability

## Answer:

The option that shows a** valid distribution** is the probability distribution in **option A. **

### Why is this a valid probability distribution?

In a probability distribution, all the **probabilities **given must **add up to 1. **

Of the given functions, only the distribution in A has that quality:

**Distribution A: Distribution B:**

= 0.45 + 0.16 + 0.39 = -0.14 + 0.6 + 0.25 + 0.29

= 1 = 1 but probability can’t be

negative

**Distribution C: Distribution D:**

= 0.45 + 1.23 – 0.87 +0.19 = 0.87 + 0.56 + 1.38

= 1 but probabililty can’t be negative = 2.81

In conclusion,** option A **is correct.

A 2-column table labeled Probability Distribution B has 4 rows. The first column is labeled x with entries 1, 2, 3, 4. The second column is labeled P (x) with entries 0, 0.45, 0.16, 0.39.

The first column is labeled x with entries 1, 2, 3, 4. The second column is labeled P (x) with entries negative 0.14, 0.6, 0.25, 0.29.

A 2-column table labeled Probability Distribution C has 4 rows. The first column is labeled x with entries 1, 2, 3, 4. The second column is labeled P (x) with entries 0.45, 1.23, negative 0.87, 0.19.

A 2-column table labeled Probability Distribution D has 4 rows. The first column is labeled x with entries 1, 2, 3, 4. The second column is labeled P (x) with entries 0.87, 0.56, 0, 1.38.

They would certainly hopefully help the student resolve the question by obtaining the questions and answer examples. You could then have a discussion with your classmate and continue the school learning by studying the subject alogside each other.